Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6. (1 point)
оy+ 3 = -6(х + 2)
оy+ 2 = 6(х + 3)
оy - 3= -6(х - 2)
оy - 2 = 6(х - 3)

y + 3 = -6(x+2)   (( y = -6x - 15 ))

Step-by-step explanation:

The main way to start doing this is to either graph each one or make every equation solving for y; as in slope-intercept form (y = mx +b).

This will turn each possible answer into

a. y = -6x - 15

b. y = 6x + 16

c. y= -6x + 15

d. y= 6x - 16

If we graph each one on a graph then find the point (-2, -3) to see if it is on the line; the equation that has (-2, -3) on the line is the answer.

In this case the answer is a. y = -6x - 15

it’s supposed to be -4+45=41

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl