According to benford's law, the probability that the first digit of the amount of a randomly chosen invoice is a 1 or a 2 is 0.477. you examine 90 invoices from a vendor and find that 29 have first digits 1 or 2. if benford's law holds, the count of 1s and 2s will have the binomial distribution with =90 and p=0.477. too few 1s and 2s suggests fraud. what is the approximate probability of counting 29 or fewer 1s and 2s if the invoices follow benford's law? use normal approximation to solve the problem, if its conditions are met.
a. 0.9855
b. 0.0145
c. 0.9984
d. 0.0016

side side side

side angle angle

angle side angle

side angle side

step-by-step explanation:

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c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

3x + 4y -25 =0 represents the amount of change sianna should recieve