Let the joint pdf of x and y be f (x, y) = 12e−4x−3 y , x > 0, y > 0. a. find the marginal pdf ’s of x and y. b. are x and y independent? c. find the conditional pdf f1(x|y). d. find the marginal cdf ’s of x and y. e. find p(1 < y < 3). f. find p(1 < y < 3|x = 3). g. find p(x > 2, 1 < y < 3).

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

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guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

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its the second choice.

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the elements in the range will be 7 less than the elements in the domain.

hi do you need an answer for your question?

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