Four whole numbers are each rounded to the nearest 10. the sum of the four rounded numbers is 90. what is the maximum possible sum of the original four numbers?

Whats the highest number each number can go up to before it rounds up? Its +4 as each number will round up otherwise. So if the rounded up numbers were 10,20,30,30. They can go up to 14,24,34,34. So its 106.please mark as brainliest

Step-by-step explanation:

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2