The voltage v in a simple electrical circuit is slowly decreasing as the battery wears out. the resistance r is slowly increasing as the resistor heats up. use ohm's law, v = ir, to find how the current i is changing at the moment when r = 465? , i = 0.09a, dv/dt =-0.03v/s, and dr/dt = 0.03? /s. (round your answer to six decimal places.)

The current I is changing at -0.000012.

Step-by-step explanation:

Given : The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR

To find : How the current I is changing at the moment.

Solution :

We have given,

R = 465\ ohm, I = 0.09A, and

Using Ohm's law, we find V

Re-write ohm's law in terms of I,

Derivate w.r.t to t,

Substitute the values given,

The current I is changing at -0.000012.

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

thats not a system of equations, that is a solution