Astronomers estimate that as many as 100 billion stars in the milky way galaxy are encircled by planets. if so, we may have a plethora of cosmic neighbors. let p denote the probability that any such solar system contains intelligent life. you would like to estimate, how small can p be and still give a 50-50 chance that we are not alone. what probability distribution will be used?

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

2 x t divided by n

step-by-step explanation:

b) well because you get well

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.