An auto mechanic converts a metric part to 0.492 in. the part comes only in fractional sizes given to the nearest 64th of an inch. what would be the closest size?

the closest part the mechanic can chose is 0.5 inch

Step-by-step explanation:

fractional sizes given to the nearest 64th of an inch = 1/64 = 0.0156

the closest size to 0.492in = 0.492 + 0.0156 = 0.5076 inches

approximately, the closest part the mechanic can chose is 0.5 inch

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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