Acoin has probability p of landing heads when tossed. a test will be made of the hypotheses h0 : p ≤ 0.1 versus h1 : p > 0.1, as follows. the coin will be tossed once. if it comes up heads, h0 will be rejected. if it comes up tails, h0 will not be rejected. if the true value of p is 0.1, what is the probability that the test results in a type i error? the probability is

b

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

i agree because i see the other persons thinking is clear