![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{6}{7}}[x-\stackrel{x_1}{(-3)}]\implies y+1=\cfrac{6}{7}(x+3) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{7}}{7(y+1)=7\left( \cfrac{6}{7}(x+3) \right)}\implies 7y+7=6(x+3)\implies 7y+7=6x+18 \\\\\\ 7y=6x+11\implies -6x+7y=11\implies 6x-7y=-11](/tpl/images/0373/3241/83fa5.png)
6x−5y=−13
6x−7y=11
Mathematics, 14.11.2019 02:31 justkevin1231
What is the equation of this line in standard form?
6x−5y=−13
6x−7y=11
6x−7y=−11
7x−6y=11
Answers: 3
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You know the right answer?
What is the equation of this line in standard form?
6x−5y=−13
6x−7y=11
6x−5y=−13
6x−7y=11
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