Astudent takes a 32-question multiple-choice exam, but did not study and randomly guesses each answer. each question has three possible choices for the answer. find the probability that the student guesses more than 75% of the questions correctly.

0.774193548

Step-by-step explanation:

I intend to use the simplest method to solve this problem, without using any complex probability theorems but a very simple but absolutely correct technique.

We know Probability is defined as ;

P = (Number of Required Outcomes)/ (Number of Possible outcomes)

PLEASE NOTE THAT THE TECHNIQUE AM ABOUT TO USE MAKES ONE ASSUMPTION; All that is most important is that the student scores 75% exactly, and the method can continue iteratively.

NOW BACK TO SOLUTION

P = (Number of Required Outcomes)/ (Number of Possible outcomes)

FINDING REQUIRED OUTCOME

75% of 3 choice multiple exam consisting of 32 questions will be

75% of (32 × 3 )

= 0.75 of (96)

= 72.

FINDING POSSIBLE OUTCOMES

100% of (32 × 3)

= 1.00 of (96)

= 96

PROBABILITY OF THE STUDENT GUESSING 75% CORRECTLY IS

72/96 = 0.774193548

To get more than 75% we can iteratively determine the answer. But we know that the value will keep decreasing. I can define one formula for the iterative analysis.

[(O.75+0.010.24) of 96 / (96)]

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

idk

step-by-step explanation: