Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $ 45 . for one performance, 30 advance tickets and 20 same-day tickets were sold. the total amount paid for the tickets was $ 1150 . what was the price of each kind of ticket?

The price of an advance ticket = 25$

The price of a same day ticket = 20 $

Step-by-step explanation:

Given there are two types of tickets:

(i)  Advance, call it A and

(ii) Same - day, call it S.

Now it is also given that the combined cost of them is 45$.

⇒                                            A + S = 45$                      (1)

Also given is that 30 Advance tickets and 20 same day tickets are sold for a total of 1150 $. Mathematically representing this would be:

                                       30 A + 20 S = 1150 $              (2)

Now we have to solve Equations (1) and (2) to get values for A and S.

To do that multiply (1) by 30 and subtract (1) and (2).

We will get S = 20. Substitute this in (1). We get A = 25.

Thus, we say the cost of an Advance ticket is 25$ and

The cost of a same day ticket is 20$.

10

step-by-step explanation:

7+3=10

idk

step-by-step explanation: