Is ∆jkl ≅ ∆kjm ? justify your answer below.

Yes, the triangles are congruent by ASA

Step-by-step explanation:

we know that

If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)

In this problem

LK=MJ

∠KLJ=∠KMJ

∠LKJ=∠MJK

so

Two angles and the included side is equal in triangle JKL and triangle KJM

therefore

JKL≅KJM > by ASA

Step-by-step explanation:

∠JLK = ∠KMJ

LK = MJ

∠LKJ = ∠MJK

∆JKL ≅ ∆KJM     {Angle side Angle - ASA congruence}

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3