Estimate the moment of inertia of a bicycle wheel 72 cm in diameter. the rim and tire have a combined mass of 1.4 kg . the mass of the hub can be ignored. express your answer to two significant figures and include the appropriate units.

0.18 kg.m²

Step-by-step explanation:

Moment of Inertia (I) = m r² (1)

Where

m= mass of the rim and tire

r = radius

I = mr² (2)

m =1.4kg

r =72/2

 = 36cm

 = 0.36 m

Substituting into (2), we have :

I = 1.4  x(0.36)²

 = 0.18144‬

≈ 0.18 kg.m²

it would open into a square depending on the type of envelope i’m not sure about the second part