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1.)what is the slope of a line that is perpendicular to a line whose equation is 5y=10+2x ?

2.)line a is represented by the equation y=−2x+3 .
how do these equations compare to line a?
categories: parallel to line a, perpendicular to line a, neither parallel nor perpendicular to line a. equations: y=2x-1, y=-2x+5, y=1/2x+7.

3.)what is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?

1.)

2.) y = 2x - 1 is neither parallel nor perpendicular to line a.

y = - 2x + 5 is parallel to line a.

line is perpendicular to line a.

3.)2x + 5y = -10

Step-by-step explanation:

1.) Given straight line is 5y = 10 + 2x

⇒

So, the slope of the given line is

Therefore, the slope of the straight line which is perpendicular to the above line will be

{Since the product of slopes of two perpendicular straight line is -1}

2.) Line a is y = - 2x + 3

Now, y = 2x - 1 is neither parallel nor perpendicular to line a.

y = - 2x + 5 is parallel to line a.

And line is perpendicular to line a.

3.) The equation of the straight line which is parallel to line 2x + 5y = 10 will be 2x + 5y = c, where c is any constant.

If this parallel line passes through (5,-4), then c = 2(5) + 5(- 4) = -10

So the equation of the parallel line is 2x + 5y = -10 (Answer)