Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail (upper) test, z subscript pequals2.12, and alphaequals0.10 b) one-tail (lower) test, z subscript pequalsnegative 1.32, and alphaequals0.05 c) two-tail test, z subscript pequalsnegative 1.56, and alphaequals0.05 d) two-tail test, z subscript pequals2.37, and alphaequals0.02

a) reject the null hypothesis

b) not reject the null hypothesis

c) not reject the null hypothesis

d) reject the null hypothesis

Step-by-step explanation:

a) one-tail (upper) test, z Subscript p equals 2.12, and alpha equals 0.10

Since p(z)=0.017 < 0.10, the result is significant.

b) one-tail (lower) test, z Subscript p equals negative 1.32, and alpha equals 0.05

Since p(z)=0.093> 0.05 the result is not significant.

c) two-tail test, z Subscript p equals negative 1.56, and alpha equals 0.05

Since p(z)=0.119>0.05 the result is not significant.

d) two-tail test, z Subscript p equals 2.37, and alpha equals 0.02

Since p(z)= 0.018<0.02 the result is significant.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.