What are the solutions to the quadratic equation (5y + 6)2 = 24? y = startfraction negative 6 + 2 startroot 6 endroot over 5 endfraction and y = startfraction negative 6 minus 2 startroot 6 endroot over 5 endfraction y = startfraction negative 6 + 2 startroot 6 endroot over 5 endfraction and y = startfraction 6 minus 2 startroot 6 endroot over 5 endfraction y = startfraction negative 4 startroot 6 endroot over 5 endfraction and y = startfraction negative 8 startroot 6 endroot over 5 endfraction y = startfraction 4 startroot 6 endroot over 5 endfraction and y = startfraction 8 startroot 6 endroot over 5 endfraction