What is the probability that exactly 10 customers will arrive in 1 hour, when the mean arrival rate is 15 customers per hour, and interarrival times are exponentially distributed?
a. 0.0486
b. 0.1185
c. 0.0699
d. 0.9301
e. 0.8815

a. 0.0486

Step-by-step explanation:

Given that  the mean arrival rate is 15 customers per hour, and interarrival times are exponentially distributed

When the interarrival times are exponential, no of customers arriving per hour is Poisson with mean = 15

The probability that exactly 10 customers will arrive in 1 hour

where X is a Poisson random variable with mean = 15

Thus we find that probability is 0.04861 and round it off to 4 decimals

Prob = 0.0486

Hence option a is right

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: