In a survey of 100 adults, 91 of them said that they trusted dna testing. a. what is pˆ , the sample proportion of adults who trust dna testing? b. find and interpret the 98% confidence interval for the proportion of adults that trust dna testing

a) The sample proportion of adults who trust DNA testing is p=0.91.

b) 98% CI:

We can claim with 98% confidence that the real proportion of adults that trust DNA is between 0.84 and 0.98.

Step-by-step explanation:

a) In this problem, we calculate p-hat, the sample proportion of adults who trust DNA testing, as

b) The z-value for a 98% CI is z=2.326.

The standard deviation of the proportion is:

Then we can define the CI as:

We can claim with 98% confidence that the real proportion of adults that trust DNA testing is between 0.84 and 0.98.

c

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)