Aradar antenna, making one revolution every 5 seconds, is located on a ship that is 6 km from a straight shoreline. how fast is the radar beam moving along the shoreline when the beam makes an angle of 45◦ with the shore?

The figure below is showing the situation:

Figure

Now let the point is at a distance x from the shoreline where it is making the angle of 45 degrees.

So we have:

x

=

6

tan

θ

Now we have:

d

θ

d

t

=

2

π

5

So we have to find the velocity that is given by:

d

x

d

t

=

d

d

θ

(

6

tan

θ

)

=

6

sec

2

(

θ

)

d

θ

d

t

=>

d

x

d

t

=

6

sec

2

(

π

4

)

2

π

5

is the required velocity

Step-by-step explanation:

does that answer your question

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

step-by-step explanation: