With two reapers operating, a field can be harvested in 1 h. if only the newer reaper is used, the crop can be harvested in 1.2 h. how long would it take to harvest the field using only the older reaper?

The older repear will harvest in 6 hrs

Explanation:

Given a field can be harvested in 1 hr with 2 reapers

Consider the total field to be 1

Let x be the time of older’s reaper

The field can be harvested in 1.2 hr with newer reaper alone

Older’s time of harvesting = per hour

Newer’s time of harvesting = per hour

Total (Older+Newer) = 1 = }

1.2 + x = 1.2x

1.2 = 0.2x

x = 6

Therefore, older repear will harvest in 6 hrs

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

sorry i got nothing

step-by-step explanation: