What is the axis of symmetry of the equation?
y = (x - 3)^2 + 4

x = -3
x = 3
x = -4
x = 4

x = 3

Step-by-step explanation:

The standard form of a parabola (x^2 function) is:

If we algebraically manipulate this, we can have the vertex form:

Where

x = h will be the axis of symmetry

k will be the vertical shift

(h,k) would be the vertex

Now, the function given in this problem is given in vertex form:

From the original vertex form, we can say that this equation has the folllowing variable values:

a = 1

(3,4) is the vertex

x = 3 is the axis of symmetry

4 is the vertical shift

We are concerned with axis of symmetry. Thus, we can see that

x = 3 is the axis of symmetry

x = 3

Step-by-step explanation:

Every quadratic is symmetrical about the line: x = h, where h is the x-coordinate of the vertex

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.