Iinvested a total of $2300 in mutual funds. one fund earned 9% profit while the other earned 4% profit. if the investors total profit was $172, how much was invested in each fund

$1600 invested in 9% fund

$700 invested in 4% fund

Step-by-step explanation:

Let

amount invested in 9% account be "x"

so

amount invested in 4% account would be "2300 - x"

The profit from the account would be the percentage (in decimal) multiplied with the amount invested in that account. So,

Profit in 9% account:

9% = 9/100 = 0.09

0.09 * x

0.09x

Profit in 4% account:

4% = 4/100 = 0.04

0.04(2300-x)

92 - 0.04x

Total profit = 0.09x + 92 - 0.04x

This is equal to 172. We equate this and find x:

Now,

2300 - x = 2300 - 1600 = 700

Hence,

$1600 invested in 9% fund

$700 invested in 4% fund

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;