Amathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown. if an examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems, in how many ways can the questions and problems be chosen?

450 ways

Step-by-step explanation:

Given that a mathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown.

An examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems

8 multiple choice questions can be selected from 10 in 10C2 ways and 3 open ended problems in 5/c3 ways

In 450 ways  the questions and problems can be chosen

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

step-by-step explanation:

one day the were 5 ducks, and their king told them to multiply their kingdom. so each went their own seperate way and met 4 other ducks on their journey.

when the ducks returned to their kingdom, it was discovered that there were 5 groups of 5 ducks. when the kind counted the number of ducks in total (including the ones he sent out earlier) he counted 25.

therefore 5 times 5 is 25.

the end. : )