Aspotlight is made by placing a strong light bulb inside a reflective paraboloid formed by rotating the parabola x2=3y around its axis of symmetry (assume that x and y are in units of inches). in order to have the brightest, most concentrated light beam, how far from the vertex should the bulb be placed? express your answer as a fraction or a decimal rounded to two decimal places.

  3/4 inch

Step-by-step explanation:

Where p is the distance from the focus to the vertex, the equation of a parabola can be written ...

  4py = x^2

The equation given here is ...

  3y = x^2

so, we have ...

  4p = 3

  p = 3/4 . . . . . . divide by 4

The distance from the focus to the vertex is 3/4 inch.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.