The circuit above has a current of 0.32 a coming out of the power supply. resistors r1, r2, and r3 have resistances of 408 latex: \omegaω, 2,296 latex: \omegaω, and 3,309 latex: \omegaω respectively, what is the voltage of the power supply

1924 volts

Step-by-step explanation:

From Ohm's Law:

Voltage  (V) = Current (I) x Resistance (R)

                V=   I R (1)

I = 0.32 A

R₁ = 408 Ω

R₂ =  2,296Ω

R₃ =   3,309Ω

Total Resistance =   408 + 2296+3309

                            =   6,013‬Ω

Substituting into  (1), we have :

V= 0.32 x  6,013‬

 =  1,924.16‬ volts

 ≅ 1924 volts

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.