Acompany produces a women's bowling ball that is supposed to weigh exactly 14 pounds. unfortunately, the company has a problem with the variability of the weight. in a sample of 11 of the bowling balls the sample standard deviation was found to be 0.71 pounds. construct a 95% confidence interval for the variance of the bowling ball weight. assume normality.

Step-by-step explanation:

Given : A company produces a women's bowling ball that is supposed to weigh exactly 14 pounds.

Sample size : n=11

Degree of freedom =n-1=10

Sample standard deviation : s= 0.71 pounds

Significance level for 95% confidence interval :

We assume that the bowling ball weight is normally distributed.

Using chi-square distribution table, the required critical values are :-

Then, the 95% confidence interval for the variance of the bowling ball weight will be :

∴ The 95% confidence interval for the variance of the bowling ball weight will be :

the solution is h=10 because you add 9 to each side of the equation.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted