Two square plots of land contains 74square feet. if the side of one plot is 2 feet longer than the side of other plot, find the dimension of both plots

The area of other plot = s² = 5² = 25  sq feet

The area of one plot = ( 5 + 2 )² = 7² = 49  sq feet

Step-by-step explanation:

Given as :

The total area of two square plots = 74 sq feet

Let The side of other plot = s    feet

So, The side of one plot = ( s + 2 )   feet

Now ,

∵ Area of square = side²

 Area of other plot = s²

 Area of one plot = ( s + 2 )²

As, The total area of two square plots = 74 sq feet

So ,  s²  + ( s + 2 )² = 74 sq feet  

Or,   s² + s² + 4s + 4 = 74

Or,   2s² + 4s - 70 = 0

Or,    s² + 2s - 35 = 0

Or,    s² -5s + 7s - 35 = 0

Or,    s ( s - 5) + 7 ( s - 5 ) = 0

So,   ( s - 5 ) ( s + 7 ) = 0

∴      s = 5 , - 7

Thus The area of other plot = s² = 5² = 25  sq feet

And The area of one plot = ( 5 + 2 )² = 7² = 49  sq feet  Answer

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