Right triangle abc has legs ac and bc of lengths 16mi and 24mi accordingly. find the distance of point b from the line that contains the median am.

9.6 mi

Step-by-step explanation:

in right triangle ABC,

AC = 16 mi

BC = 24 mi

If AM is the median, then CM = MB = 12 mi

Consider triangles CAM and EBM. In these triangles,

So, triangles CAM and EBM are similar by AA postulate.

Similar triangles have proportional corresponding sides, so

By the Pythagorean theorem,

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

include a picture of the drawing in order for me to

step-by-step explanation: