Suppose that the average number of accidents occurring on a highway each day is 3.5. find the probability that at least two accidents occur today. find the probability that at most one accident occurs today.

0.1359

Step-by-step explanation:

This is a Poisson distribution. The formula for calculating Poisson distribution is given as :

P (X = x) =

λ = 3.5

To find the probability that at most one accident occur today implies that , accident might not happen at all , the maximum accident that can happen is 1, substituting this into the formula , we have

P(X=0) =

P(X=0) = 0.0302

P(X=1) =  

P(X=1) = 0.1057

Therefore , the probability that at most one accident occurs today.

= 0.0302 + 0.1057

= 0.1359

P(x=2) =  

P(X=2) = 0.1850

the answer is 0.071

good luck! : d

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316