Ten slips of paper numberd 1 through 10 are placed in a bag. you draw a slip at random and draw another without replacing the first. find the probabilty that both numbers are odd

Probability that both numbers are odd =2/9

Step-by-step explanation:

Odd numbers are numbers such that, when they divide 2, there is a remainder.

Ten slips of paper numbered 1 through 10 are placed in a bag.

In number one to ten, the odd numbers are 1, 3,5,7 and 9

They all divide 2 and leaves a remainder.

Total number of odd numbers is 5

Total number of both odd and even numbers from one through 10 is 10

Probability of picking an odd number

= number of odd numbers/ total numbers.

Probability of picking an odd number

= 5/10= 1/2

Probability of picking another odd number without replacement is 4/9

Probability that both numbers are odd = 1/2 × 4/9 =2/9

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

a

step-by-step explanation: