Twice last month, judy carter rented a car from a car rental company and traveled around the southwest on business. the company rents its car for a daily fee, plus an additional charge per mile driven. judy recalls that her first trip lasted 4 days, she drove 450 miles, and the rental cost her $ 196.00 . on her second business trip she drove 200 miles in 3 days, and paid $ 125.00 for the rental. find the daily fee, and find the mileage charge.

$31 and $0.16

Step-by-step explanation:

Let the rental company rents its car for a $x daily fee and a $y as the mileage charge.

So, on his first trip Judy drove 450 miles for 4 days and the rental cost was $196.

So, 4x + 450y = 196 (1)

⇒ 12x + 1350y = 588 (a)

On his second trip Judy drove 200 miles for 3 days and the rental cost was $125.

Hence, 3x + 200y = 125 (2)

⇒ 12x + 800y = 500 (b)

Now, solving equations (a) and (b) we get,  

550y = 88

⇒ y = $0.16

Now, from equation (2) we get 3x = 125 - 200y = 93

⇒ x = $31

So, the daily fee is $31 and the mileage charge is $0.16. (Answer)

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy