Pl
if the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g? a. -7 and -3 b. 3 and 7 c. -7 and 3 d. -3 and 7

answer:

−13x^2 − 130x − 273

= -13(x^2 + 10x + 21)

= - 13(x + 3)(x + 7)

- 13(x + 3)(x + 7) = 0

x + 3 = 0; x = -3

x + 7 = 0; x = -7

answer

d) x = −7 or x = −3

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: