According to a report for veterinarians in the united states, 36.5 percent of households in the united states own dogs and 30.4 percent of households in the united states own cats. if one household in the united states is selected at random, what is the probability that the selected household will own a dog or a cat? (a)0.111(b) 0.331(c) 0.558(d) 0.669(e) not enough information is given to determine the probability.

Answer :E) Not enough information is given to determine the probability.

Step-by-step explanation:

Le A denotes the event that households in the United States own dogs .

and B denotes the event that households in the United States own cats.

As per given , we have

P(A)=36.5%= 0.365

P(B)=30.4% = 0.304

To find the probability that the selected household will own a dog or a cat, we apply the following formula :

P(A or B)=P(A)+P(B)+P(A and B)

But P(A and B) is not given to us.

i..e the probability that a house hold own both a cat and adg is not given to us.

Therefore, The correct option is (E) Not enough information is given to determine the probability.

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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