Mathematics, 19.11.2019 00:31 neariah24
Time spent using e-mail per session is normally distributed, with mu equals μ=13 minutes and sigma equals σ=2 minutes. complete parts (a) through (d). a. if you select a random sample of 50sessions, what is the probability that the sample mean is between 12.8 and 13.2 minutes? b. if you select a random sample of 50sessions, what is the probability that the sample mean is between 12.5 and 13 minutes? c. if you select a random sample of 100sessions, what is the probability that the sample mean is between 12.8 and 13.2 minutes? d. explain the difference in the results of (a) and (c). choose the correct answer below. the sample size in (c) is greater than the sample size in (a), so the standard error of the mean (or the standard deviation of the samplingdistribution) in (c) is ▼ less greater than in (a). as the standard deviation ▼ increases decreases , values become ▼ less more concentrated around the mean. therefore, the probability of a region that includes the mean will always ▼ decrease increase when the sample size increases.
Answers: 2
Mathematics, 21.06.2019 20:00
Ialready asked this but i never got an answer. will give a high rating and perhaps brainliest. choose the linear inequality that describes the graph. the gray area represents the shaded region. y ≤ –4x – 2 y > –4x – 2 y ≥ –4x – 2 y < 4x – 2
Answers: 1
Mathematics, 21.06.2019 20:00
Last one and the bottom answer choice is y=(x-4)^2+1 you guys!
Answers: 1
Mathematics, 22.06.2019 03:00
Ashley spent half of her lunch money on a turkey sandwich. then she spent two-thirds of the money she had left on a bottle of juice and the rest of the money on a cookie. if the cookie cost $.75, how much lunch money did ashley have to start with?
Answers: 2
Time spent using e-mail per session is normally distributed, with mu equals μ=13 minutes and sigma e...
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