The force f applied on a spring to stretch it by x centimeters is given by the equation f = kx, where k is the spring’s constant. the table gives the force applied in newtons and the corresponding elongation of the spring in centimeters. find the force applied when the spring is stretched to 1.8 centimeters.

x(in cm) y(in newtons)
0.2 3.95
0.4 8.05
0.6 11.99
0.8 16.06
1 19.98
a.
32 newtons
b.
33 newtons
c.
34 newtons
d.
35 newtons
e.
36 newtons

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

answer: 12   they all have at least 28 days

step-by-step explanation: haha

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh