An experiment consists of choosing an urn with the following probabilities that urn 1, urn 2, or urn 3 will be chosen: 1/2, 1/4, and 1/4, respectively. urn 1 contains 15 brown marbles and 14 clear marbles. urn 2 contains 6 brown marbles, 11 clear marbles and 9 red marbles. urn 3 contains 7 brown marbles, 8 clear marbles and 5 red marbles.

a marble is then chosen from the chosen urn. what is the probability that urn 3 was chosen, given that the marble chosen was clear?

a) 0.1000

b) 0.4000

c) 0.1333

d) 0.3063

e) 0.2236

option E

Step-by-step explanation:

let E₁ be the event of urn 1

let E₂ be the event of urn 2

let E₃ be the event of urn 3

P(E₁) =

P(E₂) =

P(E₃) =

Let A be the probability of getting clear marble

P(A/E₁) = =0.483

P(A/E₂) = = 0.423

P(A/E₃) = =  0.4

required probability

P(E₃/A) =

P(A) = P(E₁)P(A/E₁) + P(E₂)P(A/E₂) +P(E₃)P(A/E₃)

P(A) = 0.5 x 0.483  + 0.25 x 0.423 +0.25 x 0.4

P(A) = 0.447

now,

P(E₃/A) =

P(E₃/A) = 0.2147

hence, the correct answer is option E

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0

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step-by-step explanation:

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