Astore sells two types of toys, a and b. the store owner pays $8 and $14 for each one unit of toy a and b respectively. one unit of toys a yields a profit of $2 while a unit of toys b yields a profit of $3. the store owner estimates that no more than 2000 toys will be sold every month and he does not plan to invest more than $20,000 in inventory of these toys. how many units of each type of toys should be stocked in order to maximize his monthly total profit?

A = 1333 and B = 667

Step-by-step explanation:

Given that a store sells two types of toys, A and B.

      AB

cost       814

Profit23

Objective is to maximize profit

where A = no of toys of A and B = no of toys of B

Constraints are

By solving this equation, we get

(A,B)= (1333,667)

Corner points would be lowest of x and y intercepts in both

(A,B) = (2000,0) and (0,1428)

Profit for

Profit for

Profit for

Since maximum at (1333,667) we find that

to maximize profit A = 1333 and B = 667 to be produced.

you have to put the graph on here with the question

step-by-step explanation:

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.