Two cars started at the same position and were driven through a city using different streets. the red car traveled north 2 miles, then east 4 miles, and then south 6 miles. the green car traveled south 4 miles and then east 4 miles. both cars ended at the same location.

which best compares the motion of the cars?

the red car traveled a shorter distance, but the displacement of the cars was equal.
the green car traveled a shorter distance, but the displacement of the cars was equal.
the green car had a shorter displacement, but the distance traveled by the cars was equal.
the red car had a shorter displacement, but the distance traveled by the cars was equal.

Answer : The correct option is, The green car traveled a shorter distance, but the displacement of the cars was equal.

Step-by-step explanation :

Displacement : It is the change in the position of an object that means the minimum distance measuring from starting position to the final position. It is a scalar quantity.

Distance : It is the length of the space between the two points.  It is the length of the total route traveled by an object.

The distance traveled by red car = 2 + 4 + 6 = 12 miles

The distance traveled by green car = 4 + 6 = 8 miles

Displacement of red and green car =   (By Pythagoras theorem)

As per question, the red car traveled a greater distance and green car traveled a shorter distance but the displacement of the cars was equal.

Hence, correct option is, The green car traveled a shorter distance, but the displacement of the cars was equal.

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: