Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth

The numbers are : -20,-18,-16,-14

Step-by-step explanation:

Let 1st even integer be

So, next consecutive even integer would be

3rd consecutive even integer would be

4th consecutive even integer would be

Sum of first three integers would be

It says sum of the first three is 2 more than twice the fourth,

So we have

using distribution to simplify.

Subtracting from both sides

Subtracting 6 from both sides

∴

So first integer =-20

2nd integer  

3rd integer

4th integer  

So, the numbers are : -20,-18,-16,-14

so, converting firstly the mixed fractions to improper fractions and then "adding".

answer:   y=2x-3

step-by-step explanation: