Find two consecutive integers such that the sum of their squares is 145.

8 and 9 or -9 and -8

Step-by-step explanation:

Let be the first of the two integers. Then, since the numbers are consecutive, is the other integer. We then know that the sum of the squares of and is equal to 145. So, now we have the equation

which can be expanded and simplified to

which then gives us the quadratic equation

This can then be factored into

Which can be simplified further into

So either or . This gives us two solutions: 8 and 9 or -9 and -8.

Hope this helps! CHEERS!

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

step-by-step explanation: