Your utility company charges 14 cents per kilowatt-hour of electricity. complete parts (a) and (b) below.

a. what is the daily cost of keeping lit a 1001-watt light bulb for 12hours each day?

b. how much will you save in a year if you replace the bulb with an led bulb that provides the same amount of light using only 10 watts of power?

The daily cost of the bulb is US$ 1.68 and I'll save US$ 607.07 annually if I replace the bulb with and LED bulb

Step-by-step explanation:

Cost of kilowatt-hour of electricity = US$ 0.14 for 1,000 watts

Part A.  What is the daily cost of keeping lit a 1001-watt light bulb for 12 hours each day? And for solving part B, we should calculate the annual cost  as well.

Daily cost of the bulb = Cost of kilowatt-hour * Number of hours * electricity consumption

Daily cost of the bulb = 0.14 * 12 * 1.001

Daily cost of the bulb = US$ 1.68 (Rounding to two decimal places)

Annual cost of this bulb = Daily cost * 365

Annual cost of this bulb = 1.68 * 365

Annual cost of this bulb = US$ 613.20

Part B. How much will you save in a year if you replace the bulb with an LED bulb that provides the same amount of light using only 10 watts of power?

Daily cost of the bulb = Cost of kilowatt-hour * Number of hours * electricity consumption

Daily cost of the bulb = 0.14 * 12 * 0.01 (Consumption = 10/1,000)

Daily cost of the bulb = 0.0168

Annual cost of the bulb =  Daily cost * 365

Annual cost of the bulb =  0.0168 * 365

Annual cost of the bulb = US$ 6.13 (Rounding to two decimal places)

Savings = Cost of the first bulb in part A - Cost of the second bulb in part B

Savings = 613.20 - 6.13

Savings = US$ 607.07

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.