The possible outcomes for tossing a coin four times are shown below.

1. t-t-t-t 5. t-h-t-t 9. h-t-t-t 13. h-h-t-t
2. t-t-t-h 6. t-h-t-h 10. h-t-t-h 14. h-h-t-h
3. t-t-h-t 7. t-h-h-t 11. h-t-h-t 15. h-h-h-t
4. t-t-h-h 8. t-h-h-h 12. h-t-h-h 16. h-h-h-h
tails = t heads = h

if a coin is tossed four times, what is the probability of getting exactly zero heads?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

2 liters for 10   people

step-by-step explanation: