What is the distance covered by a train while slowing down from
20 ms−1 to 6 ms−1 with a uniform deceleration of 1.6 ms-2?

answer step by step! the answer is 113.75, but i m getting -113.75, i don't know how to fix this.

answer step by

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6

Or uniform acceleration, a = - 1.6

Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

18

step-by-step explanation:

ik this stuph and i am smart donkey

f(x) = y

f(-3) = -5

step-by-step explanation: