For the following system, use the second equation to make a substitution for y in the first equation.

3x + y = 1
y + 4 = 5x

what is the resulting equation?

3x + 5x - 4 = 1
3x + 4 - 5x = 1
3x + 5x + 4 = 1

Option A: 3x + 5x - 4 = 1

Step-by-step explanation:

Given that:

3x + y = 1   eq1

y + 4 = 5x eq2

Now for substitution in eq1 we will get a value of y from eq2:

y = 5x - 4

Substituting in eq1 we get:

3x + 5x - 4 = 1

i hope it will help you!

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5