Suppose that an outbreak of cholera follows severe flooding in an isolated town of 2500 people. initially (day 0), 30 people are infected. every day after, 18% of those still healthy fall ill. by what day will at least 87% of the population be infected?

On 11th day ( approx )

Step-by-step explanation:

Since, if a population change with a constant rate,

Then final population,

Where,

P = initial population,

r = rate of change per period,

t = number of periods,

Given,

Initial population = 2500,

Out of which, infected population = 30,

So, healthy people, initially = 2500 - 30 = 2470

Every day after, 18% of those still healthy fall ill.

So, after x days the number of healthy people,

Now, if 87% of 2470 are ill,

Then reaming healthy population = (100 - 87)% of 2470

= 13% of 2470

= 321.10

If P = 321.10,

From equation (1),

Hence, by 11 day at least 87% of the population be infected.

1/2*qr*rs

step-by-step explanation: