Classify each system of equations as having a single solution, no solution, or infinite solutions.
(y = 5 - 2x
4x + 2y = 10)
(x = 26 - 3y
2x + 6y = 22)
(5x + 4y = 6
10x – 2y = 7)
(x + 2y = 3
4x + 8y = 15)
(3x + 4y = 17
-6x = 10y - 39)
(x + 5y = 24
5x = 12 - y)

This system has infinitely many solutions because both equations represents the same line. Notice that if we multiply the first equation by 2, it will results in the same equation than the second one.

Let's multiply the first equation by -2 and sum

Notice that the result is false. Therefore, this system has no solution.

Let's multiply the first equation by -4 and sum

As you can see, the system has no solutions.

Let's multiply the first equation by -2 and sum

Now, we find the other value

The solution of the system is (4/5, 1/2). Therefore, the system has one solution.

Let's multiply the first equation by 2 and sum

Then, we find the other value

So, the system has a solution, which is (7/3 , 5/2).

Let's multiply the first equation by -5 and sum

Then, we find the other value

Therefore, the system has one solution, which is (1.5, 4.5).

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

45

step-by-step explanation: