Which of the following exponential functions represents the graph below?

Equation D give the graph given.

Step-by-step explanation:

See the graph given.

It is clear from the graph that it passes through (0,1) point.

So, putting x = 0, we get y = 1 from equation B or equation D.

Now, as the x value increases in the negative direction i.e. -5, -6, .... so on, the y value tends to zero.  

This is only possible in equation D i.e. .

So, equation D gives the graph given. (Answer)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?