On a coordinate plane, triangle a b c has points (1, 1), (4, 0), (3, 5).what is the area of triangle abc?

7 square units.

Step-by-step explanation:

On the coordinate plane, triangle ABC has vertices at (1,1), (4,0) and (3,5).

So, the area of the triangle ABC is given by  

square units. (Answer)

We know the formula that area of triangle having vertices at , , and is given by  

Δ =

Area of Triangle ABC =  unit² or 7.32 unit²

Step-by-step explanation:

Given coordinates of Triangle are

A = ( 1 , 1)

B = ( 4 , 0)

C = ( 3 , 5)

So , The measure of side AB is

AB =

or, AB =  

Or, AB =  

∴  AB =

Again ,

The measure of side BC is

BC =

or, BC =  

Or, BC =  

∴  BC =

Similarly ,

The measure of side CA is

CA =

or, CA =  

Or, CA =  

∴  CA =

Now, let D be the mid points of side BC

So, Points ( D ) =  ,  

I.e points d =    ,  

Or, points D = ,

Now Measure of line AD is

AD =  

AD = +  

Or, AD =( )² + ( )²

Or, AD =

Now, Area of Triangle ABC = × length × base

or, Area of Triangle ABC = × AD × BC

or, Area of Triangle ABC = ×   ×  

Or, Area of Triangle ABC = unit²   or , 7.32  unit² Answer

the answer

b. they are parallel and will never intersect.