Astudy was done to determine the average number of homes that a homeowner owns in his or her lifetime. for the 60 homeowners surveyed, the sample average was 4.2 and the sample standard deviation was 2.1. calculate the 95% confidence interval for the true average number of homes that a person owns in his or her lifetime.
a) (3.90, 4.50)
b) (3.66, 4.74)
c) (4.01, 4.39)
d) (3.67, 4.73)

D) (3.67, 4.73)

Step-by-step explanation:

Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where

And margin of error (ME) can be calculated as

ME= where

Putting the numbers we get ME=≈0.53

Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

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yes

step-by-step explanation: