What is the length of a rectangle with an area of 8/10 square feet and a width of 2 1/4

The length of the rectangle=16/45 feet

Step-by-step explanation:

The area of a rectangle is given by;

A=L×W

where;

A=area of the rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

A=(8/10) square feet

L=unknown

W=2 1/4 feet=9/4 feet

replacing;

8/10=l×9/4

l=8/10×4/9

l=16/45 feet

The length of the rectangle=16/45 feet

sine

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a